(3x^3+9x^2+8x+4)/(x+2)

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Solution for (3x^3+9x^2+8x+4)/(x+2) equation:


D( x )

x+2 = 0

x+2 = 0

x+2 = 0

x+2 = 0 // - 2

x = -2

x in (-oo:-2) U (-2:+oo)

(3*x^3+9*x^2+8*x+4)/(x+2) = 0

3*x^3+9*x^2+8*x+4 = 0

3*x^3+9*x^2+8*x+4 = 0

{ 1, -1, 2, -2, 4, -4 }

1

x = 1

3*x^3+9*x^2+8*x+4 = 24

1

-1

x = -1

3*x^3+9*x^2+8*x+4 = 2

-1

2

x = 2

3*x^3+9*x^2+8*x+4 = 80

2

-2

x = -2

3*x^3+9*x^2+8*x+4 = 0

-2

x+2

3*x^2+3*x+2

3*x^3+9*x^2+8*x+4

x+2

-3*x^3-6*x^2

3*x^2+8*x+4

-3*x^2-6*x

2*x+4

-2*x-4

0

3*x^2+3*x+2 = 0

DELTA = 3^2-(2*3*4)

DELTA = -15

DELTA < 0

x in { -2}

x+2 = 0

1 = 0

x belongs to the empty set

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